Team:USTC-China/results

1. Test the character of the modified pRM of being

activated by the CI.

To test the activation and inhibition of pRM, we measure the fluorescence intensity of prm-gfp, plac-gfp and plac-cI-prm-gfp.

a. plac-gfp

Initially, we use IPTG to activate the promoter plac. However, we find that the leak expression of plac is quite high. Even without the existence of IPTG, GFP expresses. This is because there are no lacI genes on the plasmid bones PSB1C3. And K12 strains can not express enough lacI to repress the expression of plac. We look into some documents and find that glucose can repress the expression of plac. Therefore, we set four experimental groups, adding glucose with concentration of 500mM, 800mM, 1000mM, 1000mM of IPTG and a blank group with nothing added.

From Figure 1. , we can see the unit fluorescence intensity of experimental groups with glucose added is lower than the blank group, because glucose represses the expression of plac, which reduces the expression of GFP.

At the beginning, we can’t observe the activating effect of IPTG on plac, which we ascribe to the unstability of the promoter plac. About 90 minutes later, the unit fluorescence intensity of experimental groups with IPTG added is higher than the blank group, which indicates IPTG’s activation on plac.

The difference of the unit fluorescence intensity between the experimental groups with different concentrations of glucose added is not strictly related to the increasing amount of glucose, because glucose affects the growth and metabolism of E.coli, which brings uncertainty to our experiments.

About 3 hours later, the difference of the unit fluorescence intensity between the groups abates, because of the consumption of glucose.

b. prm-gfp

Figure 2 shows that the fluorescence intensity of prm-gfp is so weak in comparison with plac-gfp that we can assume that the leak expression of prm is very few, which doesn't affect our experiments.

c. plac-cI-prm-gfp

Figure 3 shows similar effects of glucose and IPTG on plac-cI-pRM-gfp. pRM is activated by the protein cI. By adding IPTG, plac is activated, which leads to the production of the protein cI. With the existence of cI, pRM-GFP starts to work. On the contrast, glucose represses the expression of plac, which reduces the protein cI. Therefore, pRM expresses little and the unit fluorescence intensity of experimental groups with glucose added is the lowest.

Figure 4 shows the difference of the unit fluorescence intensity between plac-gfp and plac-cI-pRM-gfp. Generally, the fluorescence intensity of plac-gfp is higher than that of plac-cI-pRM-gfp, because the transcription efficiency of pRM is quite low, which reduces the expression of gfp in comparison with plac-gfp.

In conclusion, pRM works as we expect.

2. Test the ability of the anticro to repress the expression of the crogfp.

a. Difference between pCon(0.244) and pCon(0.856)

Figure 5 shows the difference in intensity of expression of pCon(0.244) and pCon(0.856). Obviously pCon(0.856) expresses much stronger than pCon(0.244).

b. function of anticro

To test the function of antisense RNA to cro (anticro) we have constructed, we measure the fluorescence intensity of plac-anticroT-pcon(0.856)-crogfp and plac-cI-prm-anticroT-pcon(0.856)-crogfp.

At the beginning, the unit fluorescence intensity of the experimental groups with glucose added is the lowest, because glucose promotes the growth of E.coli., which makes the rate of fluorescence divided by OD lower than the other two groups.

About 45 minutes later, the unit fluorescence intensity of experimental groups with glucose added is higher than the blank group, because glucose represses the expression of plac, which reduces the transcription of anticro. Therefore, the translation of crogfp is repressed less and the unit fluorescence intensity is higher.

On the contrast, IPTG activates plac, which increases the transcription of anticro. Anticro binds to the mRNA crogfp and represses its translation.

Figure 7. shows similar effects of glucose and IPTG on plac-cI-pRM-anticroT-pcon(0.856)-crogfp. pRM is activated by the protein cI. By adding IPTG, plac is activated, which leads to the production of the protein cI. With the existence of cI, pRM-anticroT starts to work and antirco represses the translation of crogfp. On the contrast, glucose represses the expression of plac, which reduces the protein cI. pRM expresses less and the translation of crogfp is repressed less. Therefore, the unit fluorescence intensity of experimental groups with glucose added is the highest.

From Figure 8 and Figure 9 , we can prove that anticro has the function to repress the translation of crogfp. The difference of unit fluorescence intensity in Figure 9. is much less obvious than that in Figure 8. because pCon(0.244) expresses relatively low. (Without enough time, we have not constructed the circuit plac-cI-pRM-anticroT-pCon(0.244)-crogfp.)

Above all, these results show reliable evidence that the genetic circuits we have constructed function well.

3. Evaluate the effect of the basic expression level of the lysis on the growth of bacteria.

Stability is particularly important to our system because we have lysis gene in it.If not,cells die easily and the system will go to crash soon.The practicability demands that our engineered bacteria won't die too much to influence the daily manufacture under normal conditions.To prove this,we did experiments and here are our results.

We measured the growth curve of our engineered E.coli strain with part pRM-anticro-pRM-lysis on plasmid pSB1C3 which is our final circuit and an E.coli strain with part croGFP on plasmid pSB1C3 which hardly influence the growth as the control group.It is known that the growth curve obey the model:

x is the concentration of microbe.x₀ is the initial concentration when t=t₀.μ_m is the natural growth rate.

Calculate the natural logarithm of both side of the equation,we can get:

Obviously,the variable lnx is linear to the variable t.And the slope is μ_m.

We calculate the natural logarithm of OD600 data we get and do linear fit to the data.Then we get the slope which is the natural growth rate μ_m.

We assume that μ_m can reflect the rate of cells death caused by the basic expression of lysis.If the death effect can't be ignored,the value of μ_m obtained from the experimental group will be obviously less than the control group.

The growth curve(fig.1) seems not so typical,probably because the bacteria may sense the environmental press at early stage.But since the two curve is similar,we can assert that our circuit is not the cause of the difference. Analyzing the two figures(fig.1&fig.2),we can see the first four data points lie in the logarithmic phase, and the ln(OD600) is linear to t(time).

Figure 1 Growth curve of the two groups. (a)experiment group prm-anticro-prm-lysis (b)control group croGFP

Figure 2 Points of ln(OD600) to t. (a)experiment group prm-anticro-prm-lysis (b)control group croGFP

We select the four data points and do linear fit. Then we can get μ_m,exp(experimental group) and μ_m,ctrl(control group).

Figure 3 Linear fit of ln(OD600) to t. (a)experiment group prm-anticro-prm-lysis (b)control group croGFP

Our data shows that μ_m,exp(experimental group) is even more than μ_{m, ctrl}(control group).Then we can conclude that our circuit is stable in usual conditions. Users need not worry about the condition that bacteria may die when nothing is happening.

4. Test our final system: fight against the lambda phage!

Phage enumerations, expressed as plaque forming units (PFU) per milliliter, were performed by the double-layer plaque titration method, which can conform the efficiency of design. During the experiment, all the E.coli strain is DH5α, while the control group and experiment group has different genes. Experimental group contained pRM-anticro-pRM-RBS-lysis-T (pSB1C3) and the control group contained RBS-crogfp-T (pSB1C3) and pRM-RBS-gfp-T (pSB1C3) respectively.

Table 1. Phage enumerations of different group with different concentrations of phage

Figure1. Phage enumerations of different group with different concentrations of phage Dilution Multiple of phage in A, B, C, D are 0, 10^-12, 10^-10, 10^-8 respectively. Group 1, 2, 3 are pRM-RBS-gfp-T (pSB1C3), RBS-crogfp-T (pSB1C3), pRM-anticro-pRM-RBS-lysis-T (pSB1C3)

This experiment directly proved the utility of our design. As the table1 and figure1, the experimental group didn't have any plaques, which indicates our design has done its job. The bacteria with pRM-RBS-gfp-T showed resistibility which is the same with another experiment. We suspicions it is the promoter pRM that impacts the resistibility to the lambda phage. The following experiments confirmed this idea. We present the following hypothesis to describe the mechanism of pRM promoter defending the phage. The promoter pRM can be both bound by protein CI and Cro, despite the protein CI is more tendentious to bind pRM. In the bacteria, the plasmid with pRM on it has high copy number, which means there are much more pRM than usual situation when the infection occurs. If the phage expresses Cro, the Cro will bind pRM, which lead to the dramatically decreasing concentration of cro. Thus, the phage will retain in Lysogenic period. However, more experiments are needed to test this hypothesis.