Team:NCTU Formosa/Modeling

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!align="center"|[[Team:NCTU_Formosa|Home]]
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<p id="back-top"><a href="#top"><span></span>Back to Top</a></p>
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!align="center"|[[Team:NCTU_Formosa/Team|Team]]
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!align="center"|[https://igem.org/Team.cgi?year=2012&team_name=NCTU_Formosa Official Team Profile]
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!align="center"|[[Team:NCTU_Formosa/Project|Project]]
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<div id="survey-p1" class="pimg" alt="Figure 1"><p class="imgcap"><b>Figure 1.</b></p></div>
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!align="center"|[[Team:NCTU_Formosa/Parts|Parts Submitted to the Registry]]
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<div id="survey-p2" class="pimg" alt="Figure 2"><p class="imgcap"><b>Figure 2.</b></p></div>
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!align="center"|[[Team:NCTU_Formosa/Modeling|Modeling]]
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<p>As we know, isobutanol is toxic to E.coli. So, we wonder how much E.coli can tolerate isobutanol. Therefore, we make a model to calculate the doubling time. According to the following figures, we realize that the maximum concentration of isobutanol that seriously hinder E.coli growth is <span class="emph">1.3%</span>. The figure gives us an important information to help us understand the growing condition of E.coli and to adjust the incubation time in our project.</p>
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!align="center"|[[Team:NCTU_Formosa/Notebook|Notebook]]
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<div id="survey-p3" class="pimg" alt="Figure 3"><p class="imgcap"><b>Figure 3.</b></p></div>
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!align="center"|[[Team:NCTU_Formosa/Safety|Safety]]
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<div id="survey-p4" class="pimg" alt="Figure 4"><p class="imgcap"><b>Figure 4.</b></p></div>
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!align="center"|[[Team:NCTU_Formosa/Attributions|Attributions]]
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<p>According to the equation of Thomas Robert Malthus, we can get the doubling time of E.coli in the following table.</p>
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      </div>
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If you choose to include a '''Modeling''' page, please write about your modeling adventures here. This is not necessary but it may be a nice list to include.
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<div id="counter"><img src="https://static.igem.org/mediawiki/2012/d/d1/NctuCapture.jpg" /><img src="http://s11.flagcounter.com/count/Rhz/bg_FFFFFF/txt_000000/border_CCCCCC/columns_2/maxflags_248/viewers_3/labels_1/pageviews_1/flags_1/" /><img src="https://static.igem.org/mediawiki/2012/d/d1/NctuCapture.jpg" /></div>
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    <p>Copyright © 2012 NCTU Formosa</p>
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<p>Background image belongs to <a href="http://fatezoom.deviantart.com/" target="_blank">Yuri Kormin</a>.</p>
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    <p class="author">Website designed by Calvin Hue.</p>
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Revision as of 16:23, 26 September 2012

Team:NCTU Formosa - 2012.igem.org

Back to Top

Figure 1.

Figure 2.

As we know, isobutanol is toxic to E.coli. So, we wonder how much E.coli can tolerate isobutanol. Therefore, we make a model to calculate the doubling time. According to the following figures, we realize that the maximum concentration of isobutanol that seriously hinder E.coli growth is 1.3%. The figure gives us an important information to help us understand the growing condition of E.coli and to adjust the incubation time in our project.

Figure 3.

Figure 4.

According to the equation of Thomas Robert Malthus, we can get the doubling time of E.coli in the following table.