Illumination

In Strickland's paper, it's mentioned that they used 8000 mcd LEDs from [http://www.theledlight.com theledlight.com], with 20º viewing angle and 468 nm at 3.4 V.

It's also mentioned that a single LED was used per tube, with a cross section of 0.12 cm² = 1.2x10^-5 m².

20º viewing angle, 0.35 rad, means a solid angle of 2π(1-cos(0.35)) = 0.381 sr.

This gives a luminous flux of 0.381*8 = 3.05 lm.

The illuminance should then be 3.05/1.2x10^-5 = 2.54x10⁵ lux (or lm/ m²).