Acceleration Modeling

Basic Assumptions

1. Our protein clusters locate on the membrane, which means the products of over device diffuse in an area of hemisphere. We assume that the membrane has no extra effect on the behavior of molecular diffusion. So the concentration will be doubled compared to the diffusion progress in a volume of sphere.

2. The primarysubstrate concentration remains the same in the cell cytoplasm.

3. The products of our cluster enzyme diffuse as the diffusion equation. The diffusion equation is a partial differential equation which describes density dynamics in a material undergoing diffusion. It is also used to describe processes exhibiting diffusive-like behavior, which means the diffusion rate is proportional to the gradient of density.

4. Each our membrane device occupies an area of membrane, adjacent to the others. Because each device is the same as others, the diffusion of the products out of the area can be regarded as reflected by the imaginary barrier, which means the normal derivative at the edge of the area is 0.

5. The enzyme can be regarded as a thermal source, producing the molecular at a rate of v.

Modeling Results

Based on diffusion equation, by solving it under different boundary values, we found that the cluster system can increase production significantly.

Acceleration Model

Diffusion Model

The diffusion area is regarded as a hemisphere which radius is R with an enzyme located on the center which occupies a region of r₀. So we have the equaction:

• ∂u/∂t-a² ∇² u=f(r)

• u(r,0)=0

• ∂u/∂r (R,t)=0

While:

f(r)=(v_max [A])/(K_m+[A]), r ≤ r₀ or

f(r)=0, r > r₀

By solving the equations we can show how the concentration floats with radius and time (Fig.1 ):

Fig.1 : Diffusion Model (left) and the comparison of concentration at different distance

Diffusion Model with Production Consumption

We place another downstream enzyme beside the current enzyme, so the production will be consumed. The consumption rate is considered to be Michaelis-Menten equation, and simplified as proportional to the product concentration.

• ∂u/∂t-a² ∇² u=f(r)

• u(r,0)=0

• ∂u/∂r(R,t)=0

While:

f(r)=(v_max [A])/(K_m+[A]), r ≤ r₀ or

f(r)=0, r > r₀ or

f(r)=-βu, r∈Φ

Then we have three-dimensional graphics as following (Fig.2 ):

Fig.2 : Membrane Cluster Diffusion Model near/far

To compare the concentration at different distance we have:

Fig.3 : Comparison of concentration at different distance in Membrane Cluster Diffusion Model

Enzymatic Reaction with Product Inhibition

• d[P]/dt=k₂ [ES]

• [E][S]/[ES]=k_-1/k₁ =K_s

• [E][P]/[EP]=K_P

Solving these equations we have:

• d[P]/dt=(v_max [S])/(K_s (1+[P]/K_P)+[S])

• [P]=(-(K_s+[S] )+((K_s+[S])²+2v_max[S]K_s t/K_P )^0.5)/(K_s/K_P )

Fig.4 : Production in enzymatic reaction with product inhibition

Discussion

As we assumed that the area we chose is a closed region, the products cannot diffuse to the outer side of the area. However when we are using the system in the situation of industry, most of the products can diffuse through the membrane and enter the culture medium. Under this situation the equilibrium will be changed. Reaction beside the membrane barrier can enhance the process the trans-membrane transportation as the concentration of products is much higher than the cytoplasm. Consequently there will be a dramatic increase in product amount.