Team:USP-UNESP-Brazil/Plasmid Plug n Play/Modeling

From 2012.igem.org

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\end{align}
\end{align}
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For a 800 <span class="math"><em>b</em><em>p</em></span> gene and 50 <span class="math"><em>μ</em><em>L</em></span> of solution we have: <br /><span class="math">$n_{mols} = \frac{m_{dna}}{800*6*10^{23}.10^{-12}} \simeq m_{dna} 2*10^{-15}$</span><br /> and <br /><span class="math">$[So] = \frac{m_{dna} 2*10^{-15}}{50*10^{-6}}  
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For a 800 <span class="math"><em>b</em><em>p</em></span> gene and 50 <span class="math"><em>μ</em><em>L</em></span> of solution we have:  
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\simeq m_{dna} 0.4*10^{-10} M = 0.04 m_{dna} $</span><br /> nM. This means, for example, that in order to obtain <span class="math">10</span> <span class="math"><em>n</em><em>M</em></span> of concentration <span class="math">250</span> <span class="math"><em>n</em><em>g</em></span> of DNA are needed in a solution of <span class="math">50<em>μ</em><em>L</em></span>.</p>
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\begin{align}
 +
n_{mols} = \frac{m_{dna}}{800*6*10^{23}.10^{-12}} \simeq m_{dna} 2*10^{-15}
 +
\end{align}
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and  
 +
\begin{align}
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[So] = \frac{m_{dna} 2*10^{-15}}{50*10^{-6}} \simeq m_{dna} 0.4*10^{-10} M = m_{dna}*0.04  nM.
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\end{align}
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This means, for example, that in order to obtain <span class="math">10</span> <span class="math"><em>n</em><em>M</em></span> of concentration <span class="math">250</span> <span class="math"><em>n</em><em>g</em></span> of DNA are needed in a solution of <span class="math">50<em>μ</em><em>L</em></span>.</p>
<h1 id="results">Results</h1>
<h1 id="results">Results</h1>

Revision as of 01:56, 26 September 2012