Team:Amsterdam/modeling/generaldesign

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\begin{aligned}
\begin{aligned}
\frac{dP_{0}}{dt} &=& k\ P_{0+1}\ (1 - \frac{P_{0+1}}{\text{Ca}}) - \omega\ S(t)\ P_{0} - \alpha\ P_{0} \\
\frac{dP_{0}}{dt} &=& k\ P_{0+1}\ (1 - \frac{P_{0+1}}{\text{Ca}}) - \omega\ S(t)\ P_{0} - \alpha\ P_{0} \\
-
\frac{dP_{1}}{dt} &=& \omega\ S(t)\ P_{0} - \alpha\ P_{1}\end{aligned}
+
\frac{dP_{1}}{dt} &=& \omega\ S(t)\ P_{0} - \alpha\ P_{1}
 +
\end{aligned}
$$
$$
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<center>
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<br>Table 1</br>: Parameter and initial species values for the plasmid methylation model
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Parameter and initial species values for the plasmid methylation model [tab:populationparms]
 
Using the parameter values of Table [tab:populationparms] a simulation with a duration of 40 time units is shown in Figure [fig:timelapse]. The plasmid population within a is shown to be completely converted to methylated plasmids shortly after . As long as the signal is still present – until <math>s_{\text{off}}</math>, – the bit on all newly copied plasmids will be immediately methylated as the signal is still present. After <math>s_{\text{off}}</math>, <math>F(t)</math> will start to decrease. This is mostly due to cell division, during which the cell’s plasmids will be binomially distributed between the two two daughter cells, hence halving the plasmid amount every division cycle. In this simulation, this degradation due to cell division has accounted for in the constant degradation rate <math>\alpha</math>. The duration of time after which a small trail of methylated plasmids is still present is related to two factors: positively to the amount of methylated cells at <math>s_{\text{off}}</math> and negatively to the plasmid degradation rate.
Using the parameter values of Table [tab:populationparms] a simulation with a duration of 40 time units is shown in Figure [fig:timelapse]. The plasmid population within a is shown to be completely converted to methylated plasmids shortly after . As long as the signal is still present – until <math>s_{\text{off}}</math>, – the bit on all newly copied plasmids will be immediately methylated as the signal is still present. After <math>s_{\text{off}}</math>, <math>F(t)</math> will start to decrease. This is mostly due to cell division, during which the cell’s plasmids will be binomially distributed between the two two daughter cells, hence halving the plasmid amount every division cycle. In this simulation, this degradation due to cell division has accounted for in the constant degradation rate <math>\alpha</math>. The duration of time after which a small trail of methylated plasmids is still present is related to two factors: positively to the amount of methylated cells at <math>s_{\text{off}}</math> and negatively to the plasmid degradation rate.

Revision as of 05:54, 21 September 2012