Team:USP-UNESP-Brazil/Associative Memory/Modeling

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with the rate $\beta$.
with the rate $\beta$.
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The authors designed some experiments in order to estimate the constants, table 1. For example, the values for $K$ and $r$ were determined by  
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The authors designed some experiments in order to estimate the constants, Figure 1. For example, the values for $K$ and $r$ were determined by examination of the growth curve. </p>
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examination of the growth curve. </p>
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=KxRphis_alpha.jpg | caption=Fig. 1. The fraction of the up-regulated population as a function of the carrying capacity ($K$) and the ratio $\frac{\phi_A}{\phi_B}$ for the case $\phi_B = \alpha$, at equilibrium. Initial conditions: $N_{Au} = N_{Bu} = A = B = 0$. | size=620px}}
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=TableMatModelQS.jpeg | caption=Fig. 1. Parameter values obtained by Ward et al. | size=350px}}
In our model, there are two different types of population of bacteria and each type has his own QSM, represented by $A$ and
In our model, there are two different types of population of bacteria and each type has his own QSM, represented by $A$ and
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<h1 id="model">Results</h1>
<h1 id="model">Results</h1>
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We first evaluated the fraction of cells up-regulated as a function of carrying capacity and of the ratio $\frac{\phi_A}{\phi_B}$,
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We first evaluated the fraction of up-regulated cells as a function of the carrying capacity ($K$) and of the $\frac{\phi_A}{\phi_B}$ ratio, and $K$ turned out to be an important parameter of the model. For values of $K$ up to $10^8$, in the equilibrium, no population can reach the quorum state, since the density of cells is too low. On the other hand, for values higher than $10^8$ the population
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that has a higher repression rate, represented by $\phi$, reaches quorum and represses the other population, as presented in Figure 2.
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=TableMatModelQS.jpeg | caption=Fig. 2. Parameter values obtained by Ward et al. | size=350px}}
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=KxRphis_alpha.jpg | caption=Fig. 2. The fraction of the up-regulated population as a function of the carrying capacity ($K$) and the ratio $\frac{\phi_A}{\phi_B}$ for the case $\phi_B = \alpha$, at equilibrium. Initial conditions: $N_{Au} = N_{Bu} = A = B = 0$. | size=620px}}
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The carrying capacity is an important parameter of the model. For values up to $10^8$, in the equilibrium, no population can reach
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quorum since the density of cells is too low, Figure 1. On the other hand, for values higher than $10^8$ the population
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that has a higher repressive rate, represented by $\phi$, reachs quorum and represses the other population.  
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<h1 id="model">Equilibrium points </h1>
<h1 id="model">Equilibrium points </h1>
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\begin{align}  
\begin{align}  
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& \frac{y(\kappa_{Bu} - \kappa_{Bd}) + \kappa_{Bd}}{\alpha_B (1-y) + \lambda^*_B + y\phi_B} = \frac{\Big[x(\kappa_{Au} - \kappa_{Ad}) + \kappa_{Ad}\Big]\alpha_A (1-x)} {\Big[\alpha_A (1-x) + \lambda^*_A + y\phi_A\Big]x\phi_B} - \frac{\beta_A}{\phi_B} \\  
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\hspace{-0.5 cm} \frac{y(\kappa_{Bu} - \kappa_{Bd}) + \kappa_{Bd}}{\alpha_B (1-y) + \lambda^*_B + y\phi_B} = \frac{\Big[x(\kappa_{Au} - \kappa_{Ad}) + \kappa_{Ad}\Big]\alpha_A (1-x)} {\Big[\alpha_A (1-x) + \lambda^*_A + y\phi_A\Big]x\phi_B} - \frac{\beta_A}{\phi_B} \\  
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& \frac{x(\kappa_{Au} - \kappa_{Ad}) + \kappa_{Ad}}{\alpha_A (1-x) + \lambda^*_A + x\phi_A} = \frac{\Big[y(\kappa_{Bu} - \kappa_{Bd}) + \kappa_{Bd}\Big]\alpha_B (1-y)} {\Big[\alpha_B (1-y) + \lambda^*_B + x\phi_B\Big]y\phi_A} - \frac{\beta_B}{\phi_A}
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\hspace{-0.5 cm} \frac{x(\kappa_{Au} - \kappa_{Ad}) + \kappa_{Ad}}{\alpha_A (1-x) + \lambda^*_A + x\phi_A} = \frac{\Big[y(\kappa_{Bu} - \kappa_{Bd}) + \kappa_{Bd}\Big]\alpha_B (1-y)} {\Big[\alpha_B (1-y) + \lambda^*_B + x\phi_B\Big]y\phi_A} - \frac{\beta_B}{\phi_A}
\end{align}
\end{align}
where $\lambda^* = \lambda/K$, and $x$ and $y$ range from 0 up to 1. These expressions are similar, since exchanging $A$ and $B$ turns one equation into the other.
where $\lambda^* = \lambda/K$, and $x$ and $y$ range from 0 up to 1. These expressions are similar, since exchanging $A$ and $B$ turns one equation into the other.
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phisiguais1.jpg | caption=Fig. 3. Each curve represents the solution of one equation, their intersections being the equilibrium points. One is close to $(0,0)$, the other to $(1,1)$. | size=350px}}
Thus, the equilibrium points $(x,y)$ are placed in the intersection between the solutions for the relations above. Depending on the set of parameters, one can find two to four equilibria - the first one close to $(0,0)$, representing the repression of both populations, and the second one close to $(1,1)$, representing the activation of both populations, as presented below:
Thus, the equilibrium points $(x,y)$ are placed in the intersection between the solutions for the relations above. Depending on the set of parameters, one can find two to four equilibria - the first one close to $(0,0)$, representing the repression of both populations, and the second one close to $(1,1)$, representing the activation of both populations, as presented below:
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phisiguais1.jpg | caption=Fig. 3. Each curve represents the solution of one equation, their intersections being the equilibrium points. There is one close to $(0,0)$ and another close to $(1,1)$.} | size=350px}}
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phis100.jpg | caption=Fig. 4. When $\frac{\phi_A}{\phi_B} \gg 1$, besides the equilibria close to $(0,0)$ and $(1,1)$, there is also a point close to to $(1,0)$. | size=350px}}
A third equilibrium point emerges when $\frac{\phi_A}{\phi_B} \gg 1$ - which means the repression of population A over population B is much greater than its counterpart. In this case, the system reaches an equilibrium close to $(1,0)$: population A activated, population B repressed. The behavior is analogous if $\frac{\phi_A}{\phi_B} \ll 1$.
A third equilibrium point emerges when $\frac{\phi_A}{\phi_B} \gg 1$ - which means the repression of population A over population B is much greater than its counterpart. In this case, the system reaches an equilibrium close to $(1,0)$: population A activated, population B repressed. The behavior is analogous if $\frac{\phi_A}{\phi_B} \ll 1$.
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phis100.jpg | caption=Fig. 4. When $\frac{\phi_A}{\phi_B} \gg 1$, besides the equilibria close to $(0,0)$ and $(1,1)$, there is also a point close to to $(1,0)$$.} | size=350px}}
 
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phis100ab.jpg | caption=Fig. 4. When $\frac{\phi_A}{\alpha_A} \gg 1$ and $\frac{\phi_B}{\alpha_B} \gg 1$, there are four equilibria, close to $(0,0)$, $(1,1)$, $(1,0)$ and $(0,1)$.} | size=350px}}
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Finally, when both $\phi_A$ and $\phi_B$ are big when compared to $\alpha_A$ and $\alpha_B$, both populations A and B are able to  
Finally, when both $\phi_A$ and $\phi_B$ are big when compared to $\alpha_A$ and $\alpha_B$, both populations A and B are able to  
repress each other, depending on the initial conditions: there are equilibria both close to $(1,0)$ and to $(0,1)$ - with repression  
repress each other, depending on the initial conditions: there are equilibria both close to $(1,0)$ and to $(0,1)$ - with repression  
of one population and activation of the other.
of one population and activation of the other.
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{{:Team:USP-UNESP-Brazil/Templates/RImage | image=Phis100ab.jpg | caption=Fig. 4. When $\frac{\phi_A}{\alpha_A} \gg 1$ and $\frac{\phi_B}{\alpha_B} \gg 1$, there are four equilibria, close to $(0,0)$, $(1,1)$, $(1,0)$ and $(0,1)$.} | size=350px}}
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<h1 id="discussion">Discussion</h1>
<h1 id="discussion">Discussion</h1>

Revision as of 21:26, 26 September 2012