Team:EPF-Lausanne/Modeling/Bioreactor

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(Difference between revisions)
(Illumination)
(Illumination)
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In Strickland's paper, it's mentioned that they used 8000 mcd LEDs from [http://www.theledlight.com theledlight.com], with 20º viewing angle and 468 nm at 3.4 V.
In Strickland's paper, it's mentioned that they used 8000 mcd LEDs from [http://www.theledlight.com theledlight.com], with 20º viewing angle and 468 nm at 3.4 V.
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It's also mentioned that a single LED was used per tube, with a cross section of 0.12 sqcm.
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It's also mentioned that a single LED was used per tube, with a cross section of 0.12 cm<sup>2</sup> = 1.2x10<sup>-5</sup> m<sup>2</sup>.
20º viewing angle, 0.35 rad, means a solid angle of 2π(1-cos(0.35)) = 0.381 sr.
20º viewing angle, 0.35 rad, means a solid angle of 2π(1-cos(0.35)) = 0.381 sr.
This gives a luminous flux of 0.381*8 = 3.05 lm.
This gives a luminous flux of 0.381*8 = 3.05 lm.
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The illuminance should then be 3.05/1.2x10<sup>-5</sup> = 2.54x10<sup>5</sup> lux (or lm/ m<sup>2</sup>).
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Revision as of 10:18, 27 July 2012

Illumination

In Strickland's paper, it's mentioned that they used 8000 mcd LEDs from [http://www.theledlight.com theledlight.com], with 20º viewing angle and 468 nm at 3.4 V.

It's also mentioned that a single LED was used per tube, with a cross section of 0.12 cm2 = 1.2x10-5 m2.

20º viewing angle, 0.35 rad, means a solid angle of 2π(1-cos(0.35)) = 0.381 sr.

This gives a luminous flux of 0.381*8 = 3.05 lm.

The illuminance should then be 3.05/1.2x10-5 = 2.54x105 lux (or lm/ m2).