Team:USP-UNESP-Brazil/Plasmid Plug n Play/Modeling

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<h1 id="Appendix">Appendix</h1>
<h1 id="Appendix">Appendix</h1>
<h2 id="Equations">Equations</h2>
<h2 id="Equations">Equations</h2>
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<p><br /><span class="math">$  \frac{d}{dt} [S]      = k_{-1}[S_{a}] - [S] \left(k_{1}[M] + k_{d}\right) $</span><br /></p>
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<p><br /><span class="math">$  \frac{d}{dt} [S_{a}]  = k_{1}[S][M] + k_{-1}[S_{aa}] + k_{-2}[S_{ab}] - [S_{a}]( k_{1}[M] + k_{-1} + k_{2}[M] + k_{d} ) $</span><br /></p>
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\begin{align}
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<p><br /><span class="math">$  \frac{d}{dt} [S_{aa}] = k_{1}[S_{a}][M] + k_{-2}[S_{3}] - [S_{aa}](k_{2}[M] + k_{-1} + k_{d}) $</span><br /></p>
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  \frac{d}{dt} [S]      &= k_{-1}[S_{a}] - [S] \left(k_{1}[M] + k_{d}\right) \\
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<p><br /><span class="math">$  \frac{d}{dt} [S_{ab}] = k_{2}[S_{a}][M] + k_{-1}[S_{3}] - [S_{ab}](k_{-2} + k_{1}[M] + k_{d}) $</span><br /></p>
+
  \frac{d}{dt} [S_{a}]  &= k_{1}[S][M] + k_{-1}[S_{aa}] + k_{-2}[S_{ab}] - [S_{a}]( k_{1}[M] + k_{-1} + k_{2}[M] + k_{d} ) \\
-
<p><br /><span class="math">$ \frac{d}{dt} [S_{3}]  = k_{1}[S_{ab}][M] + k_{2}[S_{aa}][M] + k_{-2}[S_{4}] - [S_{3}](k_{-1} + k_{-2} + k_{2}[M] + k_{d}) $</span><br /></p>
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  \frac{d}{dt} [S_{aa}] &= k_{1}[S_{a}][M] + k_{-2}[S_{3}] - [S_{aa}](k_{2}[M] + k_{-1} + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [S_{4}]  = k_{2}[S_{3}][M] + k_{-34}[I_c] - [S_{4}](k_{-2} + k_{34} + k_{d}) $</span><br /></p>
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  \frac{d}{dt} [S_{ab}] &= k_{2}[S_{a}][M] + k_{-1}[S_{3}] - [S_{ab}](k_{-2} + k_{1}[M] + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [I_c]    = k_{34}[S_{4}] + k_{-5}[L_{2}][C_{2}] - [I_c](k_{-34} + k_{-5}) $</span><br /></p>
+
  \frac{d}{dt} [S_{3}]  &= k_{1}[S_{ab}][M] + k_{2}[S_{aa}][M] + k_{-2}[S_{4}] - [S_{3}](k_{-1} + k_{-2} + k_{2}[M] + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [C_{2}]  = k_{5}[I_c] + k_{2}[C_{1}][M] - [C_{2}](k_{-5}[P_{2}] + k_{-2}) $</span><br /></p>
+
  \frac{d}{dt} [S_{4}]  &= k_{2}[S_{3}][M] + k_{-34}[I_c] - [S_{4}](k_{-2} + k_{34} + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [C_{1}]  = k_{1}[C][M] + k_{-2}[C_{2}] - [C_{1}](k_{-1} + k_{2}[M]) $</span><br /></p>
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  \frac{d}{dt} [I_c]    &= k_{34}[S_{4}] + k_{-5}[L_{2}][C_{2}] - [I_c](k_{-34} + k_{-5}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [C]      = k_{-1}[C_{1}] - k_{1}[M][C] $</span><br /></p>
+
  \frac{d}{dt} [C_{2}]  &= k_{5}[I_c] + k_{2}[C_{1}][M] - [C_{2}](k_{-5}[P_{2}] + k_{-2}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [L_{2}]  = k_{5}[I_c] + k_{2}[L_{1}][M] - [L_{2}](k_{-5}[C_{2}] + k_{-2} + k_{d}) $</span><br /></p>
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  \frac{d}{dt} [C_{1}]  &= k_{1}[C][M] + k_{-2}[C_{2}] - [C_{1}](k_{-1} + k_{2}[M]) \\
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<p><br /><span class="math">$ \frac{d}{dt} [L_{1}]  = k_{1}[L][M] + k_{-2}[L_{2}] - [L_{1}](k_{-1}+ k_{2}[M] + k_{d}) $</span><br /></p>
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  \frac{d}{dt} [C]      &= k_{-1}[C_{1}] - k_{1}[M][C] \\
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<p><br /><span class="math">$  \frac{d}{dt} [L]      = k_{-1}[L_{1}] - [L](k_{1}[M] + k_{d}) $</span><br /></p>
+
  \frac{d}{dt} [L_{2}]  &= k_{5}[I_c] + k_{2}[L_{1}][M] - [L_{2}](k_{-5}[C_{2}] + k_{-2} + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [P]      = k_{-1}[P_{1}] -  k_{1}[M][P] $</span><br /></p>
+
  \frac{d}{dt} [L_{1}]  &= k_{1}[L][M] + k_{-2}[L_{2}] - [L_{1}](k_{-1}+ k_{2}[M] + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [P_{1}]  = k_{1}[P][M] + k_{-2}[P_{2}] - [P_{1}](k_{-1} + k_{2}[M]) $</span><br /></p>
+
  \frac{d}{dt} [L]      &= k_{-1}[L_{1}] - [L](k_{1}[M] + k_{d}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [P_{2}]  = k_{5}[I] + k_{2}[P_{1}][M] - [P_{2}](k_{-5}[C_{2}] + k_{-2}) $</span><br /></p>
+
  \frac{d}{dt} [P]      &= k_{-1}[P_{1}] -  k_{1}[M][P] \\
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<p><br /><span class="math">$ \frac{d}{dt} [I]      = k_{34}[M_{4}] + k_{-5}[P_{2}][C_{2}] - [I](k_{-34} + k_{5}) $</span><br /></p>
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  \frac{d}{dt} [P_{1}]  &= k_{1}[P][M] + k_{-2}[P_{2}] - [P_{1}](k_{-1} + k_{2}[M]) \\
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<p><br /><span class="math">$ \frac{d}{dt} [E_{4}]  = k_{-34}[I] + k_{2}[E_{3}][M] - [E_{4}](k_{34}+ k_{-2}) $</span><br /></p>
+
  \frac{d}{dt} [P_{2}]  &= k_{5}[I] + k_{2}[P_{1}][M] - [P_{2}](k_{-5}[C_{2}] + k_{-2}) \\
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<p><br /><span class="math">$  \frac{d}{dt} [E_{3}]  = k_{-2}[E_{4}] + k_{2}[E_{aa}][M] + k_{1}[E_{ab}][M] - [E_{3}](k_{2}[M] + k_{-2} + k_{-1}) $</span><br /></p>
+
  \frac{d}{dt} [I]      &= k_{34}[M_{4}] + k_{-5}[P_{2}][C_{2}] - [I](k_{-34} + k_{5}) \\
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<p><br /><span class="math">$ \frac{d}{dt} [E_{aa}] = k_{-2}[E_{3}] + k_{1}[E_{a}][M] - [E_{aa}](k_{2}[M] + k_{-1}) $</span><br /></p>
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  \frac{d}{dt} [E_{4}]  &= k_{-34}[I] + k_{2}[E_{3}][M] - [E_{4}](k_{34}+ k_{-2}) \\
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<p><br /><span class="math">$  \frac{d}{dt} [E_{ab}] = k_{-1}[E_{3}] + k_{2}[E_{a}][M] - [E_{ab}](k_{1}[M] + k_{-2}) $</span><br /></p>
+
  \frac{d}{dt} [E_{3}]  &= k_{-2}[E_{4}] + k_{2}[E_{aa}][M] + k_{1}[E_{ab}][M] - [E_{3}](k_{2}[M] + k_{-2} + k_{-1}) \\
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<p><br /><span class="math">$  \frac{d}{dt} [E_{a}]  = k_{-1}[E_{aa}] + k_{-2}[E_{ab}] + k_{1}[E][M] - [E_{a}](k_{1}[M] + k_{2}[M] + k_{-1}) $</span><br /></p>
+
  \frac{d}{dt} [E_{aa}] &= k_{-2}[E_{3}] + k_{1}[E_{a}][M] - [E_{aa}](k_{2}[M] + k_{-1}) \\
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<p><br /><span class="math">$  \frac{d}{dt} [E]      = k_{-1}[E_{a}] - k_{1}[M][E] $</span><br /></p>
+
  \frac{d}{dt} [E_{ab}] &= k_{-1}[E_{3}] + k_{2}[E_{a}][M] - [E_{ab}](k_{1}[M] + k_{-2}) \\
 +
  \frac{d}{dt} [E_{a}]  &= k_{-1}[E_{aa}] + k_{-2}[E_{ab}] + k_{1}[E][M] - [E_{a}](k_{1}[M] + k_{2}[M] + k_{-1}) \\
 +
  \frac{d}{dt} [E]      &= k_{-1}[E_{a}] - k_{1}[M][E] \\
 +
\end{align}
<h1 id="references">References</h1>
<h1 id="references">References</h1>

Revision as of 18:21, 25 September 2012