Team:Amsterdam/data/background activity

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(Leaky expression rate)
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$$
$$
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[O_{\text{Free}}] = [O_{\text{Total}}] (1 + \frac{[R_{2}]}{K_{d}})
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[O_{\text{Free}}] = \frac{[O_{\text{Total}}]}{1 + \frac{[R_{2}]}{K_{d}}}
$$
$$
We immediately see that the $[O_{\text{Free}}]$ depends on $[R_{2}]$ and $O_{\text{Total}}$.
We immediately see that the $[O_{\text{Free}}]$ depends on $[R_{2}]$ and $O_{\text{Total}}$.
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The dissociation constant of the dimerized LacI-repressor for its operator sequence has been determined to be $10^{-12} M $ and the volume of ''E. coli'' is $0.7\ \mu m^{3}$.
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The dissociation constant of the dimerized LacI-repressor for its operator sequence has been determined to be $10^{-12} M $ and the volume of ''E. coli'' is $0.7\ \mu m^{3}$. Assuming $R_{2} = 200$ and $O_{\text{Total}} = 200$, we get that the operon is vacant $2.10815 \cdot 10^{-6}$ of the time.
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The transcription rate in E.coli is 40-80 bp/s.
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More simply, the leaky expression rate can also be retrieved from this [[http://oregonstate.edu/instruction/bb492/lectures/Regulation.html|website]], which states a 1000-fold decrease in expression of the repressor-bound operon compared to the free operon.
More simply, the leaky expression rate can also be retrieved from this [[http://oregonstate.edu/instruction/bb492/lectures/Regulation.html|website]], which states a 1000-fold decrease in expression of the repressor-bound operon compared to the free operon.

Revision as of 01:38, 27 September 2012